Piping on Linux Command line

[simonthecat]

I was playing with piping in linux and came up with this:

echo $PATH | tr ;  “ “

Now I want to pass that to the ls -l command so I tried this:

echo $PATH | tr ;  “ “ | ls -l

But that just lists the current working directory.

Any ideas on why this did not work?

[slacker3]

try

ls -l `echo $PATH | tr :  " "`

http://tldp.org/HOWTO/Bash-Prog-Intro-HOWTO.html
http://tldp.org/LDP/abs/html/

[simonthecat]

Hey that worked! Thank you very much slacker3!

[misson]

Alternatively,

echo $PATH | tr : ' ' | xargs ls -l

or, more appropriately,

echo $PATH | sed -E -e 's/\s/\\&/' -e 's/:/ /' | xargs ls -l

in case there are spaces in any of the paths.