Here is my code now, but it still isn't working :/
It is just writing "Database Updated With:" on the screen, but no values, and the database isn't updated.
PHP Code:
<html>
<head>
<title>Database Test</title>
<?php
// Connect to the database server
mysql_connect('localhost', 'martynba_martynb', 'mlb0891sr3dm') or die('Error connecting to the database, MySQL returned: ' . mysql_error());
// Select the database
mysql_select_db('martynba_comments') or die('Error selecting database, MySQL returned: ' . mysql_error());
//Build query
$query = mysql_query("SELECT * FROM commentTable");
//Display results
while ($row = mysql_fetch_array($query)) {
echo "<br /> ID: " .$row['ID'].
"<br /> First Name: ".$row['FNAME'].
"<br /> Last Name: ".$row['LNAME'].
"<br /> Phone Number: ".$row['PHON'];}
?>
</head>
<body>
<hr />
<form medthod="post" action="update.php">
First Name:<br />
<input type="text" name="FNAME" size="30" /><br />
Last Name:<br />
<input type="text" name="LNAME" size="30" /><br />
Phone Number:<br />
<input type="text" name="PHON" size="12" /><br />
<input type="submit" value="Update Database"/>
</form>
</body>
</html>
update.php:
PHP Code:
<?php
mysql_connect('localhost', 'martynba_martynb', 'mlb0891sr3dm') or die('Error: ' . mysql_error());
mysql_select_db('martynba_comments') or die('Error: ' . mysql_error());
$FNAME = mysql_real_escape_string($_POST['FName']);
$LNAME = mysql_real_escape_string($_POST['LName']);
$PHON = mysql_real_escape_string($_POST['PHON']);
$query = 'INSERT INTO commentTable(\'FNAME\', \'LNAME\', \'PHON\')
VALUES(\'' . $FNAME . '\', \'' . $LNAME . '\', \'' . PHON . '\')';
$result = mysql_query ($query);
echo('Database Updated With: ' . $FNAME . ' ' .$LNAME . ' ' . $PHON);
?>