Ajax with Php

[nyanko]

Well I need some script that loads this code below every x seconds or minutes automatically, I know it can be done with Ajax but cant find the way to do it, any Ajax oracle out there please help D:
I wrote this code by Myself and it works but, to do the check again, if the server is receiving connections into the ports desired, I need to Hit reload.
This is my php file:

<style type="text/css">
#ServerStatus {
    opacity: 0.75;
    background-color: #4B92B4;
    position: absolute;
    left: 10%;
    top: 20px;
    font-family: Geneva, Arial, Helvetica, sans-serif;
    font-size: 12px;
    border: solid 1px #fff;
    color:#fff;
    padding:5px;
}
</style>
<div id='ServerStatus'>
    <?php
        //config start

        $ip = 'HERE GOES THE IP';
        $logport = 'port1';
        $charport = 'port2';
        $mapport = 'port3';
        $offline = '<b><FONT COLOR=red>Offline</b>&nbsp;<img src="./images/RedDownArrow.gif" ALT="Offline"></FONT></b>';
        $online = '<b><FONT COLOR=lime>Online</b>&nbsp;&nbsp;<img src="./images/GreenUpArrow.gif" ALT="Online"></FONT></b>';

        //config end -- cheching opening listening ports

        $login = @fsockopen($ip, $logport, $num, $error, 5);
        if(!$login) {
            $login_status = $offline;
            $logy=0;
        } else {
            $login_status = $online; 
            $logy=1;
            fclose($login);
        }
        $char = @fsockopen($ip, $charport, $num, $error, 5);
        if(!$char) {
            $char_status = $offline;
            $chary=0;
        } else {
            $char_status = $online; 
            $chary=1;
            fclose($char);
        }
        $map = @fsockopen($ip, $mapport, $num, $error, 5);
        if(!$map) {
            $map_status = $offline;
            $mapy=0;
        } else {
            $map_status = $online; 
            $mapy=1;
            fclose($map);
        }
        if ($logy==1&&$chary==1&&$mapy==1){
            //Checking Users Online
            mysql_connect($ip,'worldmap','') or die();
            @mysql_select_db('epitaph');
            $query = "SELECT COUNT(*) as total FROM `char` WHERE online = '1'";
            $result = mysql_query($query);
            mysql_close();
            $arr = mysql_fetch_array($result);
            $usersonline = "<b><FONT COLOR=lime> $arr[total] </FONT></b>";
        } else 
            $usersonline = '<b><FONT COLOR=red>Offline</b>&nbsp;<img src="./images/RedDownArrow.gif" ALT="Offline"></FONT></b>';
        //Printing Results
        echo "<b>";
        echo "<tbody><table><tr><td>Server Status</tr></td>";
        echo "<tr><td>Login Server:</td><td>$login_status</td></tr>";
        echo "<tr><td>Char Server:</td><td>$char_status</td></tr>";
        echo "<tr><td>Map Server:</td><td>$map_status</td></tr>";
        echo "<tr><td>Players Online:</td><td>$usersonline</td></tr></table></tbody>";
        echo "</b>";
    ?>
</div>

Edit:
bump D: I buried my own post with some of my responses xD

[sunils]

you can google for ajax script here. google for ajax script calling server function...

here is some of the link that i found out

http://en.wikipedia.org/wiki/XMLHttpRequest

you have to use the XMLHTTPRequest function to do that..

Here is another link...with help of jquery...

http://roshanbh.com.np/2008/03/call-...nd-jquery.html

[jhahoney]

try http://www.w3schools.com and goto AJAX tutorials, its superb

[nyanko]

Thanks :3
I will try, besides I didn't want to use XMLHTTPRequest cause it shows the activex thing on IE
Edit:
Thanks I got it solved, now I know Ajax :P.

Wheres the close button :o? :lockd:

[phpasks]

Ajax Simple Example Download
http://www.phpasks.com/ajax/simple_ajax.html

Using Prototype js framework
http://www.phpasks.com/ajax/prototype_ajax.html