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Thread: Script Help Please

  1. 10-06-2008 08:42 PM #1
    Twinkie
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    Script Help Please

    Needless to say, I have not scripted in PHP for 3 months now and I have found my self to forget the most basic concepts. Could some one please remind me why this is not working?
    PHP Code:
    <?php
    $Info     = "None";
    function     LoadResults() {
         $Info = "It is Me!";
     return     true;
    }

    function     LogIpCount() {
         $Info = "Foriegn!";
     return     false;
    }

    if (    $_SERVER['REMOTE_ADDR']=="000.000.000.000") {LoadResults(); echo "1";}
    else {echo     "2"; LogIpCount();}

    ?>

    <html>
    meaningless code...
    <body><?php echo $Info; ?></body>
    </html>
    I was planning to put a simple IP counter for all IP addresses but my own, like a visit counter. Basically, it checks if I am the person on the web site, otherwise it assigns the value "Foriegn!" to the $Info variable which is printed some ways down the page. Even though I have proven that the IF statement evaluates correctly, for some reason, the function is unable to change the value of the variable and output is the default value: "None". Why is that, especially since it can print the default value?
    _____________
    Output: "None"

    Also, does anybody know why in certain pages, like some of the JavaScript games I have been working on, the IDs and getElementById() does not work? Is it due to improperly nested DIV, TABLES, FIELDSETS, ect?
    Last edited by Twinkie; 10-06-2008 at 08:43 PM. Reason: Automerged Doublepost
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  2. 10-06-2008 08:57 PM #2
    xav0989's Avatar
    xav0989
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    Re: Script Help Please

    PHP Code:
    <?php
    $Info     = "None";
    function     LoadResults() {
     global     $Info;
         $Info = "It is Me!";
     return     true;
    }

    function     LogIpCount() {
     global     $Info;
         $Info = "Foriegn!";
     return     false;
    }

    if (    $_SERVER['REMOTE_ADDR'] == "000.000.000.000") {
         LoadResults();
     echo     "1";
    } else {
     echo     "2";
         LogIpCount();
    }

    ?>
    <html>
    meaningless code...
    <body><?php echo $Info; ?></body>
    </html>
    Since the variable is set outsite, you need to register this variable as a global for the function to work. You may also use pointers... but that's complex.
    Quote Originally Posted by Twikie
    Also, does anybody know why in certain pages, like some of the JavaScript games I have been working on, the IDs and getElementById() does not work? Is it due to improperly nested DIV, TABLES, FIELDSETS, ect?
    Make sure you are making no mistakes, and look at the javascript error console, it helps.
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  3. 10-06-2008 09:34 PM #3
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    Re: Script Help Please

    You could also return $Info instead of true or false I guess.

    Also, please note that it is spelled "Foreign" ;)
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  4. 10-07-2008 08:17 PM #4
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    Re: Script Help Please

    Even if you change a variables content inside a function, the value of the variable will remain unchanged outside the function unless you declare it as global as xav0989 said. The simplest workaround is of course having the function return the value instead as Salvatos said. The other option is to reference the var but it's not optimal.
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  5. 10-07-2008 08:45 PM #5
    Twinkie
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    Thumbs up Re: Script Help Please

    Thanks so much guys, It is all coming back to me now! If any of you ever need help with JavaScript/AJAX/HTML, you know were to find me.

    Also, the game scripts maybe does contain some errors, but they do not show up in the error console. The script also works perfectly when I use the onclick event (which I hate using), instead of a controlled, script defined event handler. Does anybody know any good JavaScript debuggers that is better than Firefox's error console?

    PS: Now I have to read my whole bible sized PHP reference book again. :pat:
    Last edited by Twinkie; 10-07-2008 at 08:53 PM.
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  6. 10-07-2008 09:01 PM #6
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    Re: Script Help Please

    Quote Originally Posted by Twinkie View Post
    Does anybody know any good JavaScript debuggers that is better than Firefox's error console?
    Woah I didn't know about this one thanks for the info!
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  7. 10-08-2008 03:02 PM #7
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    Re: Script Help Please

    Quote Originally Posted by Twinkie View Post
    Does anybody know any good JavaScript debuggers that is better than Firefox's error console?
    You might want to take a look at javascript debugger or firebug... extensions.

    I've edited the script as you suggested
    PHP Code:
    <?php
    $Info     = "None";
    function     LoadResults() {
     return     "It is Me!";
    }

    function     LogIpCount() {
     return     "Foreign!";
    }

    if (    $_SERVER['REMOTE_ADDR'] == "000.000.000.000") {
         $Info = LoadResults();
     echo     "1";
    } else {
     echo     "2";
         $Info = LogIpCount();
    }

    ?>
    <html>
    meaningless code...
    <body><?php echo $Info; ?></body>
    </html>
    And there was a small spelling mistake too!
    Last edited by xav0989; 10-08-2008 at 03:03 PM. Reason: Small spelling mistake
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  8. 10-09-2008 02:54 PM #8
    Twinkie
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    Re: Script Help Please

    Thanks a lot for your help guys! I will look into Firebug. My script is working great now :D
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