[resolved] Using PHP to output Executable PHP

[expose]

<?php
 
$page_home = "
<?php
$conn = mysql_connect(\"*******\", \"*******\", \"*******\") or die(mysql_error());
 
mysql_select_db(\"*******\",$conn) or die(mysql_error());
$get_content = \"SELECT * FROM `\".$site.\"_home_page`;\";
$content = mysql_query($get_content,$conn);
while($content_array = mysql_fetch_array($content)){
$body = $content_array[data];
$body_output .= \"<br /><br />\".$body;
}
$get_announce = \"SELECT * FROM `\".$site.\"_home_page_announce;\";
$announce = mysql_query($get_announce,$conn);
while($announce_array = mysql_fetch_array($announce)){
$announcement = $announce_array[data];
$announcement_output .= \"<div class=\"information\">\".$announcement.\"</div><br /><br/>\";
}
 
?>
";
 
?>

The above code is outputting:

<?php = mysql_connect("*******", "*******", "*******") or die(mysql_error());
mysql_select_db("*******",) or die(mysql_error());
 
 = "SELECT * FROM `".."_home_page`;";
 = mysql_query(,);while( = mysql_fetch_array()){ 
= ;
 .= "<br /><br />".;
} 
= "SELECT * FROM `".."_home_page_announce;"; 
= mysql_query(,);
 
while( = mysql_fetch_array()){
 = ;
 .= "<div class="information">".."</div><br /><br/>";
}
 
?>

And I need it to output:

<?php
$conn = mysql_connect("*******", "*******", "*******") or die(mysql_error());
mysql_select_db(\"expose_expose\",$conn) or die(mysql_error());
$get_content = "SELECT * FROM `".$site."_home_page`;";
$content = mysql_query($get_content,$conn);
while($content_array = mysql_fetch_array($content)){
$body = $content_array[data];
$body_output .="<br /><br />".$body;
}
$get_announce = "SELECT * FROM `".$site."_home_page_announce;";
$announce = mysql_query($get_announce,$conn);
while($announce_array = mysql_fetch_array($announce)){
$announcement = $announce_array[data];
$announcement_output .= "<div class=\"information\">".$announcement."</div><br /><br/>\";
}
 
?>

Edit:
I fixed it.

<?php

$site_home = fopen("test_home.php", "w+");


//add add code to files

/*** Begin Template File ***/
$test_home = "
<?php

$"."conn = mysql_connect(\*******\", \*******\", \*******\") or die(mysql_error());
mysql_select_db(\*******\",$conn) or die(mysql_error());

$"."get_content = \"SELECT * FROM `\".$"."site.\"_home_page`;\";
$"."content = mysql_query($get_content,$conn);

while($"."content_array = mysql_fetch_array($"."content)){
$"."body = $"."content_array[data];

$"."body_output .= \"<br /><br />\".$"."body;
}

$"."get_announce = \"SELECT * FROM `\".$"."site.\"_home_page_announce;\";
$"."announce = mysql_query($"."get_announce,$"."conn);

while($"."announce_array = mysql_fetch_array($"."announce)){
$"."announcement = $"."announce_array[data];

$"."announcement_output .= \"<div class=\\\"information\\\">\".$"."announcement.\"</div><br /><br/>\";
}

?>
";
fwrite($site_home,$test_home);

fclose($site_home);

?>

 

[woiwky]

You can just place a backslash before a $ to escape it from being interpreted as a variable. However, if you don't want to have to escape $ and " in a string, then just enclose the text in single quotes.